-x^2+340x+6000=0

Solution for -x^2+340x+6000=0 equation:

-x^2+340x+6000=0

We add all the numbers together, and all the variables

-1x^2+340x+6000=0

a = -1; b = 340; c = +6000;
Δ = b2-4ac
Δ = 3402-4·(-1)·6000
Δ = 139600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{139600}=\sqrt{400*349}=\sqrt{400}*\sqrt{349}=20\sqrt{349}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(340)-20\sqrt{349}}{2*-1}=\frac{-340-20\sqrt{349}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(340)+20\sqrt{349}}{2*-1}=\frac{-340+20\sqrt{349}}{-2}
$